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Two parallel wires carry currents of 10 A and 40 A in opposite directions. Another wire carrying a current antiparallel to 10 A is placed midway between the two wires. The magnetic force on it will be.

Option: 1

Towards 20 A.


Option: 2

Towards 40 A.


Option: 3

Zero.


Option: 4

Perpendicular to the plane of the currents.


Answers (1)

best_answer

\mathrm{F_1=\frac{\mu_0(10 \times i)}{2 \pi l}\\ }

\mathrm{F_2=\frac{\mu_0(i \times 40)}{2 \pi l} }

\mathrm{\mathrm{F}_1 \text { and } \mathrm{F}_2 }  both points in the same direction towards the 40 A  wire.

Posted by

Pankaj Sanodiya

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