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Two Protons Move Parallel to each other, keeping distance r between them, both moving with same velocity \vec{V}. Then the ratio of the Electric and magnetic force of interaction between them is -

Option: 1

\frac{c^2}{v^2}


Option: 2

\frac{2 c^2}{v^2}


Option: 3

\frac{c^2}{2 v^2}


Option: 4

none


Answers (1)

best_answer

\begin{aligned} & c=\frac{1}{\sqrt{\ell_0 \varepsilon_0}} \\ & F e=\frac{k e^2}{\gamma^2}=\frac{e^2}{4 \pi \varepsilon_\gamma \gamma^2} \\ & \vec{B}=\frac{h_0}{4 \pi} \frac{\operatorname{ar}(\vec{V} \times \vec{\gamma})}{\gamma^3} \\ & B=\frac{\log v}{4 \pi \gamma^2} \\ & F m=q(\vec{V} \times \vec{B})=\frac{\mu_0 e^2 v^2}{4 \pi r^2} \\ & \therefore \text { ratio }=\frac{1}{\mu_0 \varepsilon_0 V^2}=\frac{c^2}{V^2} \\ & \end{aligned}

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