Two resistors 400\; \Omega and 800\; \Omega are connected in series across a 6\; V battery. The potential difference measured by a voltmeter of 10\; k\Omega across 400\; \Omega resistor is close to :
Option: 1 2\; V
Option: 2 1.8\: V
Option: 3 2.05\: V
Option: 4 1.95\: V

Answers (1)

From the question 

The circuit diagram is drawn as shown below

\begin{array}{l} i=\frac{6}{800+(\frac{40 \times 10000}{400+10000})} \\\\ i=\frac{6}{1184.61}=0.00506 \\ \\ V_{AB}=6-(800 \times 0.00506)=6-4.05=1.95 \end{array}

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