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  • Two spheres of the same material have radii 1 m and 4 m and temperatures 4000 K and 2000 K respectively. The ratio of the energy radiated per second by the first sphere to that by the second is

Two spheres of the same material have radii 1 m and 4 m and temperatures 4000 K and 2000 K respectively. The ratio of the energy radiated per second by the first sphere to that by the second is

Option: 1

1:1


Option: 2

16:1


Option: 3

4:1


Option: 4

1:9


Answers (1)

best_answer

Energy radiated per second is P=e.\sigma.T^{4}A

\frac{P_{1}}{P_{2}}= \left(\frac{T_{1}}{T_{2}} \right )^{4}.\left(\frac{A_{1}}{A_{2}} \right )=\left(\frac{T_{1}}{T_{2}} \right )^{4}.\left(\frac{r_{1}}{r_{2}} \right )^{2}

\frac{P_{1}}{P_{2}}= \left(\frac{4000}{2000} \right )^{4}\times\left(\frac{1}{4} \right )^{2}=1

Correct option is 1.

Posted by

Rishi

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