Get Answers to all your Questions

header-bg qa

Two waves executing simple harmonic motions travelling in the same direction with same amplitude and frequency are superimposed. The resultant amplitude is equal to the \sqrt{3} times of amplitude of individual motions. The phase difference between the two motions is_________. (degree).

Option: 1

60


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

For two waves executing simple harmonic motion travelling in the same direction, the resultant amplitude is

\mathrm{R =\sqrt{A_1^2+A_2^2+2 A_1 A_2 \cos \phi} }
\mathrm{A_1 =A_2 \quad \text { (Given) } }

\mathrm{R =\sqrt{3} A_1=\sqrt{3} A_2 \quad \text { (Given) } }

\mathrm{\therefore \sqrt{3} A_1 =\sqrt{A_1^2+A_1^2+2 A_1^2 \cos \phi} }

\mathrm{\phi =60^{\circ}}
The phase difference betwen the two motions is \mathrm{60^{\circ}}

Posted by

sudhir.kumar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE