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  • Two wires of same material and same length L but radii R and 2R respectively are joined end to end a

Two wires of same material and same length L but radii R and 2R respectively are joined end to end and a weight w is suspended from the combination as shown in the figure. The elastic potential energy in the system is-

Option: 1

\frac{3 \omega^2 L}{4 \pi R^2 y}


Option: 2

\frac{3 \omega^2 L}{3 \pi R^2 y}


Option: 3

\frac{5 \omega^2 L}{8 \pi R^2 y}


Option: 4

\frac{\omega^2 L}{\pi R^2 y}


Answers (1)

best_answer

\Delta l_1=\frac{\omega L}{\left(4 \pi R^2\right) Y}, \Delta l_2=\frac{\omega L}{\pi R^2 4}

U=\frac{1}{2} \times 4\left(\frac{4 \pi R^2}{L}\right) \times\left[\frac{\omega L}{4 \pi R^2 y}\right]+\frac{1}{2} \times \frac{y\left(\pi R^2\right)}{L} \times\left[\frac{\omega L}{\pi R^2 y}\right]^2

U=\frac{5 \omega^2 L}{8 \pi R^2 y}

Posted by

Shailly goel

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