U(atomic no.92,atomic mast 238) emits 8 alpha and 6 beeta particles.the neutron/proton ratio in the product nucleus is? Explain solution...

Answers (1)

Alpha emission : ^{A}_{Z}X \rightarrow ^{A-4}_{Z-2}X^{'} +^{4}_{2}\alpha

Beta Emission : ^{A}_{Z}X \rightarrow ^{A}_{Z+1}X^{'} +^{0}_{-1}\beta

In this problem, both alpha and beta emissions are taking place.

^{A}_{Z}U \rightarrow ^{A-8\times 4}_{Z-8\times 2+6\times 1}X^{'} +6 \times \; ^{0}_{-1}\beta + 8 \times \; ^{4}_{2}\alpha

Putting value of A and Z

^{238}_{92}U \rightarrow ^{238-8\times 4}_{92-8\times 2+6\times 1}X^{'} +6 \times \; ^{0}_{-1}\beta + 8 \times \; ^{4}_{2}\alpha

^{238}_{92}U \rightarrow ^{206}_{82}X^{'} +6 \times \; ^{0}_{-1}\beta + 8 \times \; ^{4}_{2}\alpha

Now in the product nucleus, Number of protons = 82 and number of neutrons = 206-82 =  124

Ratio of Neutron/Proton = 124/82 = 62/41

 

Preparation Products

Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout JEE Main April 2022

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 34999/- ₹ 24999/-
Buy Now
Test Series JEE Main April 2021

Take chapter-wise, subject-wise and Complete syllabus mock tests and get in depth analysis of your test..

₹ 6999/- ₹ 4999/-
Buy Now
JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
Buy Now
Test Series JEE Main April 2022

Take chapter-wise, subject-wise and Complete syllabus mock tests and get an in-depth analysis of your test..

₹ 6999/-
Buy Now
Boost your Preparation for JEE Main 2021 with Personlized Coaching
 
Exams
Articles
Questions