Using a screw ganged pitch 0.1\; cm and 50 divisions of its circular scale, the thickness of an object is measured. It should correctly be recorded as  :
 
Option: 1 2.124
Option: 2 2.21
Option: 3 2.125  
Option: 4 2.127

Answers (1)

Pitch of the circular scale \mathrm{P}=0.1 \mathrm{cm}

Number of divisions on a circular scale N=50

So least count of screw gauge L C=\frac{P}{N}=\frac{0.1}{50} \mathrm{cm}=0.002 \mathrm{cm}

So any measurement will be integral  Multiple of LC
 From the option, we can say that The answer will be 2.124 cm

Most Viewed Questions

Preparation Products

Knockout JEE Main 2021 (One Month)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Weekend Live Classes, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 14000/- ₹ 4999/-
Buy Now
Knockout JEE Main 2021

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Weekend Live Classes, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 22999/- ₹ 9999/-
Buy Now
Test Series JEE Main 2021

Chapter/Subject/Full Mock Tests for JEE Main, Personalized Performance Report, Weakness Sheet, Complete Answer Key,.

₹ 6999/- ₹ 2999/-
Buy Now
Knockout JEE Main 2022

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Live Classes(Classes will start from Last week of September), Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 34999/- ₹ 24999/-
Buy Now
JEE Main Rank Booster 2021

Booster and Kadha Video Lectures, Unlimited Full Mock Test, Adaptive Time Table, 24x7 Doubt Chat Support,.

₹ 13999/- ₹ 6999/-
Buy Now
Boost your Preparation for JEE Main 2021 with Personlized Coaching
 
Exams
Articles
Questions