Using a screw ganged pitch 0.1\; cm and 50 divisions of its circular scale, the thickness of an object is measured. It should correctly be recorded as  :
 
Option: 1 2.124
Option: 2 2.21
Option: 3 2.125  
Option: 4 2.127

Answers (1)

Pitch of the circular scale \mathrm{P}=0.1 \mathrm{cm}

Number of divisions on a circular scale N=50

So least count of screw gauge L C=\frac{P}{N}=\frac{0.1}{50} \mathrm{cm}=0.002 \mathrm{cm}

So any measurement will be integral  Multiple of LC
 From the option, we can say that The answer will be 2.124 cm

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