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wavelength of deuteron when accelerated through potential difference V is equal is

Option: 1

\frac{12.27}{\sqrt{V}}A^{\circ}

 

 

 


Option: 2

\frac{0.202}{\sqrt{V}}A^{\circ}


Option: 3

\frac{12.37}{\sqrt{V}}A^{\circ}


Option: 4

\frac{0.302}{\sqrt{V}}A^{\circ}


Answers (1)

best_answer

 

\lambda =\frac{h}{\sqrt{2mq\nu }}

h=6.62\times 10^{-31}

m_d\simeq 3.34\times 10^{-27}kg

q=1.6\times 10^{-19}C

\Rightarrow \lambda = \frac{0.202}{\sqrt{V}}A^{\circ}

Posted by

Gautam harsolia

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