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Wavelength of light used in an optical instrument are \lambda_1=4000A^0\:\:\:and\:\:\lambda_2=5000A^0  then ratio of their respective resolving powers (corresponding to \lambda_1\:\:and\:\lambda_2) is

Option: 1

16:25


Option: 2

9:1


Option: 3

4:5


Option: 4

5:4


Answers (1)

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\\ Resolving \ power\ of\ an\ optical\ instrument \propto \frac{1}{\lambda}$\\ $\frac{\text { Resolving power at } \lambda_{1}}{\text { Resolving power at } \lambda_{2}}=\frac{\lambda_{1}}{\lambda_{2}}$\\ $\left[\text { Limit of resolution } \propto \frac{1}{\text { resolving power }}\right]$\\ Ratio of resolving power $=\frac{5000}{4000}=\frac{5}{4}=5: 4$

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