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  • We are required to form different words with the help of the letters of the word INTEGER. Let be the number of

We are required to form different words with the help of the letters of the word INTEGER. Let m_1 be the number of words in which I and N are never together and m_2 be the number of words which begnning with I and end with R, then m_1 / m_2 is given by
 

Option: 1

42
 

 


Option: 2

30
 


Option: 3

6
 


Option: 4

1 / 30 


Answers (1)

best_answer

[IN] TEGER

Number of ways =\frac{6 !}{2 !} \times 2 !=6 !=720

             m_1=\frac{7 !}{2 !}-720=1800

and        [I] NTEGE   [R]

              \begin{gathered} m_2=\frac{5 !}{2 !}=60 \\ \\m_1 / m_2=30 \end{gathered}

Posted by

Gautam harsolia

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