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what is de Broglie wavelength of the wave associated with and an electron that has been accelerated through a potential difference of 50V?

Option: 1

2.7\times 10^{-10}

 

 

 


Option: 2

1.74\times 10^{-10}


Option: 3

3.6\times 10^{-9}


Option: 4

4.9\times 10^{-11}


Answers (1)

best_answer

As we learned,

De - Broglie wavelength (λ) is independent of charge

The gain of kinetic energy by an electron is eV

\frac{1}{2}mv^{2}=eV

v=\sqrt{\frac{2eV}{m}}=\sqrt{\frac{2\times 1.6\times 10^{-19}\times 50}{9.11\times 10^{-31}}}

=4.19\times 10^{6}m/s

\therefore \lambda = \frac{h}{mv}=\frac{6.62\times 10^{-34}}{9.1\times 10^{-31}\times 4,19\times 10^{6}}

= 1.74\times 10^{-10}m

Posted by

Gaurav

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