Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • What is the De-Broglie wavelength of an electron whose kinetic energy is 200 eV?Option: 1 0.005 nm<st

What is the De-Broglie wavelength of an electron whose kinetic energy is 200 eV?

Option: 1

0.005 nm


Option: 2

0.01 nm


Option: 3

 0.02 nm


Option: 4

0.04 nm


Answers (1)

best_answer

Using the equation,
\lambda= h/\sqrt{2mK}
where h is the Planck's constant, m is the mass of the particle and K is
the kinetic energy of the particle.
Given,K= 200eV
Putting the values, we get
\lambda = 6.626\times 10^{-34}/\sqrt{2\times 9.1\times10^{-31}\times10^{-19}\times200}= 0.02nm

Posted by

avinash.dongre

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JAC Chandigarh Counselling 2025: Round 1 seat allotment result out for BTech admissions
anam-khan

JoSAA round 5 seat allotment result 2025 out on josaa.nic.in
anam-khan

BTech aspirant from north-east or UT? Apply for CSAB NEUT counselling 2025 today

Latest Question