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What is the energy of a photon of wavelength 600 nm?

Option: 1

2.07 eV


Option: 2

 1.24 eV


Option: 3

3.29 eV


Option: 4

 0.62 eV


Answers (1)

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Light propagates in bundles of energy called photons. The energy of one quantum is given by the equation E= hv , where h is Planck's constant,v is the frequency of light, and c is the speed of light. The syllabus also covers the properties of photons, including their energy, momentum, mass, and behavior during collisions with other particles. It is important to note that photons are electrically neutral and do not carry any electric charge. The energy of a photon can be calculated using the equation E= hc/\lambda , where h is Planck's constant, c is the speed of light, and \lambda  is the wavelength of light.
E=h c / \lambda
=\left(6.626 \times 10^{-34} J . s \times 3 \times 10^8 \mathrm{~m} / \mathrm{s}\right) /\left(600 \times 10^{-9} \mathrm{~m}\right)
=3.31 \times 10^{-19} \mathrm{~J}
=1.24 \mathrm{eV}

Therefore, the energy of a photon of wavelength 600 nm is 1.24 eV.

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Anam Khan

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