What is the formula of the angular velocity of the particle which is performing angular SHM ??

Answers (1)

The general equation of angular SHM is given by \theta =\theta _0sin(\omega t+ \phi )

Similarly, The angular velocity if the bob which is in angular SHM is given by 

\\\dot{\theta }=\frac{d\theta }{dt}=\theta_0 \omega Cos(\omega t+\phi )\\ \\ or \ \ \dot{\theta }= \omega \sqrt{ {\theta_0 }^2-\theta ^2}

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