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  • What is the path difference between electrons scattered from adjacent crystal planes when the angle of scattering is 40 degrees and the distance between the diffracting planes is <img alt="2 \

What is the path difference between electrons scattered from adjacent crystal planes when the angle of scattering is 40 degrees and the distance between the diffracting planes is 2 \AA ?

Option: 1

0.94 \AA


Option: 2

1.31 \AA


Option: 3

2.09 \AA


Option: 4

3.26 \AA


Answers (1)

best_answer

Using the formula
\Delta x=2 d \sin \theta,
Given, d=2 \mathrm{~A}^{\circ} and \theta=40^{\circ}.
Converting the angle to radians, we get:
\theta=40^{\circ}=\frac{(40 \times \pi)}{180}=0.698 \text { radians }
Substituting the values in the formula, we get:
\Delta x=2 \AA \times \sin 0.698 \approx 1.31 \AA
Therefore, the path difference between electrons scattered from adjacent crystal planes is approximately 1.31 \AA.

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Riya

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