What is the percentage mass of N in a mixture of 0.5 mole NH3 and 1 mole Ca(NO3)2?

Answers (1)

mass % of N in mixture =(total mass of N in mixture /total mass of mixture)*100

total mass of N in mixture =0.5*14+1*2*14=35.5

total mass of mixture = 172.5

mass % of N in mixture =(35.5/172.5)*100=20.57

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