Get Answers to all your Questions

header-bg qa

What is the role of sulphonated α- naphthol in Molisch’s test?

Option: 1

To dehydrate carbohydrates
 


Option: 2

To hydrolyze carbohydrates


Option: 3

To form furfural and its derivatives

 


Option: 4

To react with furfural and its derivatives to form a colored complex


Answers (1)

best_answer

The role of sulphonated α-naphthol in Molisch's test is to react with furfural and its derivatives formed from the carbohydrates to form a colored complex. When concentrated H2SO4 or HCl is added to a carbohydrate solution in Molisch's test, the carbohydrates get dehydrated to form furfural and its derivatives. The furfural formed reacts with the sulphonated α-naphthol present in the solution to give a purple (violet-red) colored complex. The sulphonated α-naphthol acts as a coupling agent in the reaction, forming a colored complex with the furfural or its derivatives. The formation of this coloured complex is due to the presence of conjugated double bonds in the molecule, which absorbs light in the visible region of the spectrum and gives rise to the characteristic colour.

Posted by

seema garhwal

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE