What is the role of sulphonated α- naphthol in Molisch’s test?
To dehydrate carbohydrates
To hydrolyze carbohydrates
To form furfural and its derivatives
To react with furfural and its derivatives to form a colored complex
The role of sulphonated α-naphthol in Molisch's test is to react with furfural and its derivatives formed from the carbohydrates to form a colored complex. When concentrated H2SO4 or HCl is added to a carbohydrate solution in Molisch's test, the carbohydrates get dehydrated to form furfural and its derivatives. The furfural formed reacts with the sulphonated α-naphthol present in the solution to give a purple (violet-red) colored complex. The sulphonated α-naphthol acts as a coupling agent in the reaction, forming a colored complex with the furfural or its derivatives. The formation of this coloured complex is due to the presence of conjugated double bonds in the molecule, which absorbs light in the visible region of the spectrum and gives rise to the characteristic colour.
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