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What is the value of impedence in an RLC Circuit having component 

R=10 \Omega, L=5 \mathrm{H}, \quad C=0.5 \mathrm{mF},

When it is in resonance.

Option: 1

10 \Omega


Option: 2

12 \Omega


Option: 3

15.4 \Omega


Option: 4

5 \Omega


Answers (1)

best_answer

When\ RLC\ circuit\ is\ in\ resonance\ then\ impedance\ is\ given\ by :-

Z=\sqrt{R^2+\left(X_L-X_C\right)^2} .

\\where: \\ X_L=X_C\left[\because 0, \frac{1}{\omega c}=\omega L\right]

\\Hence\\ \begin{aligned} & Z=\sqrt{R^2+\left(X_L-X_C\right)^2} \\ & Z=\sqrt{R^2+0}=R \end{aligned}

\\So, \\Z=10 \Omega

 

 

Posted by

sudhir.kumar

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