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What is the wavelength of the incident beam of electrons in the Davisson-Germer experiment if the accelerating potential is 54 V?

 

Option: 1

0.592 \mathrm{~nm}


Option: 2

0.465 \mathrm{~nm}


Option: 3

0.167 \mathrm{~nm}


Option: 4

12.27 \mathrm{~A}^{\circ}


Answers (1)

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The Davisson-Germer experiment and the Frank Hertz experiment. The Davisson-Germer experiment demonstrated the wave nature of electrons through electron diffraction, and verified the de Broglie equation. The experimental setup included an electron gun, collimator, target, and detector. The scattered electrons produced a diffraction pattern and the dual nature of matter was verified. The Frank Hertz experiment verified the existence of discrete energy states in atoms, and the graph of collected current vs accelerating voltage showed a characteristic 4.9 \mathrm{~V} peak due to the ionization of mercury atoms. According to de Broglie's equation, the wavelength of the incident beam of electrons is given by  \lambda_e=\frac{12.27}{\sqrt{V}} \AA. Plugging in the values of V=54V and , 1 \AA=0.1 \mathrm{~nm} we get \lambda_e=0.167 \mathrm{~nm}, which is the correct answer.  

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Sanket Gandhi

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