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  • What is the work function of a metal whose photoelectric threshold frequency is <img alt="4.0\times 10^{14}Hz" src="https://entrancecorner.oncodecogs.com/gif.latex?4.0%5Ctimes%2010%5

What is the work function of a metal whose photoelectric threshold frequency is 4.0\times 10^{14}Hz ?

Option: 1

2.48\times 10^{-19}J


Option: 2

6.63\times 10^{-34}J


Option: 3

4.96\times 10^{-19}J


Option: 4

2.48\times 10^{-34}J


Answers (1)

best_answer

The work function \left ( \phi \right ) of a metal is given by the equation \phi= hv_{0}= hc/\lambda _{0}, where h is Planck's constant \left ( 6.63\times10^{-34}Js \right ),v_{0} is the photoelectric threshold frequency and \lambda_{0} is the photoelectric threshold wavelength. Substituting the given value of v_{0}= 4.0\times10^{14}Hz in the equation gives 

\phi=\frac{\left(6.626 \times 10^{-34} \mathrm{~J} . \mathrm{s}\right) \times\left(3.0 \times 10^8 \mathrm{~m} / \mathrm{s}\right)}{4.0 \times 10^{14} \mathrm{~Hz}}=4.96 \times 10^{-19} \mathrm{~J}
 

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jitender.kumar

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