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What will be the angular momentum of the revolving electron in 3rd orbit ?

Option: 1

9.27 \times 10^{-27} J/T


Option: 2

27.81 \times 10^{-27} J/T


Option: 3

18.54 \times 10^{-27} J/T


Option: 4

37.08 \times 10^{-27} J/T


Answers (1)

best_answer

 

 

 

                                                                                             \begin{array}{l}{\mu=n \frac{-e}{2 m_{e}} \frac{h}{2 \pi}} \\ \\ {\mu=-n \frac{e h}{4 \pi m_{e}}}\end{array}

By putting the value,    n = 3

                                    e, h and me of the electron

We will get \mu = 27.81 \times 10^{-27} J/T

 

 

Posted by

shivangi.bhatnagar

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