Get Answers to all your Questions

header-bg qa

What will be the most suitable combination of three resistors \mathrm{A=2\Omega , B=4\Omega , C=6\Omega } so that \mathrm{\left ( \frac{22}{3} \right ) } is equivalent resistance of combination?

Option: 1

Parallel combination of A and C connected in series with B.


Option: 2

Parallel combination of A and B connected in series with C.


Option: 3

Series combination of A and C connected in parallel with B.


Option: 4

Series combination of B and C connected in parallel with A.


Answers (1)

best_answer

\mathrm{ \begin{aligned} &A=2 \Omega \quad B=4 \Omega \quad C=6 \Omega \\ &R_{e q}=\left(\frac{22}{3}\right) \Omega \end{aligned} }


It is possilde when \mathrm{ A \&B} are in parallel combination and then in series combination with \mathrm{ C}

\mathrm{R_{\text {eq }}=\frac{A \times B}{A+B}+C=\frac{22}{3}}
he correct option is (2)

Posted by

Divya Prakash Singh

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE