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The equilibrium constant for a reaction is 10. what will be value of △Go?

                         R =8.314 JK−1mol−1, T=300 K

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\\\text{The equation for calculatiing delta G from the equilibirum constant.}\\\\ \Delta \mathrm{G}^{0}=-2.303 \mathrm{RT} \log \mathrm{K}=-2.303 \times 8.314 \times 300 \log 10=-5.744 \mathrm{kJ} / \mathrm{mol}

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