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When 0.002 mol of acid is added to 205 mL of a buffer solution, pH decreases by 0.02 units.The buffer capacity of the system is:

Option: 1

.04


Option: 2

0.2


Option: 3

0.3


Option: 4

0.4


Answers (1)

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\begin{array}{l}{\text { \: \: \: Buffer capacity }} {\mathrm{=\frac{\text { Number of moles per litre of acid or base added }}{\text { Change in } \mathrm{pH} \text { or } \mathrm{pOH}}}}\end{array}
[\mathrm{Acid}]=\frac{0.002 \times 1000}{250}=0.008 \mathrm{M}
\text { Buffer capacity }=\frac{0.008}{0.02}=0.4

Therefore, option(4) is correct

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sudhir.kumar

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