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  • When 10 identical cell in series are connected to the ends of a resistance of 59,the current is  found t

When 10 identical cell in series are connected to the ends of a resistance of 59\Omega,the current is  found to be 0.25A. But when the same cells being connected in parallel,are joined to the ends of a resistance of 0.05\Omega,the current is 25A internal resistance of  each cell is

Option: 1

0.1 \Omega


Option: 2

0.2 \Omega


Option: 3

0.3 \Omega


Option: 4

0.4 \Omega


Answers (1)

best_answer

 

In series E_{eq}=10E,\: \: r_{eq}= 10r

I=0.25=\frac{10E}{59+10r}

or\: \: 10E=2.5r+14.75........\left ( 1 \right )

In parallel E_{eq}=E,\: \: r_{eq}= r/10

I=25A=\frac{E}{0.05+\frac{r}{10}}

or\: \: E=1.25+2.5r........\left ( 2 \right )

From (1) & (2)

1.25+25r=2.5r+14.75

or 22.5r=2.25 or r=0.1\Omega

Posted by

Nehul

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