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  • When 200 mL of 0.2 M acetic acid is shaken with 0.6 g of wood charcoal, the final concentration of acetic acid after adsorption is 0.1 M. The mass of acetic acid adsorbed per gram of carbon is_____

When 200 mL of 0.2 M acetic acid is shaken with 0.6 g of wood charcoal, the final concentration of acetic acid after adsorption is 0.1 M. The mass of acetic acid adsorbed per gram of carbon is____________ g.

Option: 1

2


Option: 2

----------


Option: 3

-----------


Option: 4

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Answers (1)

best_answer

\mathrm{\text { moles of } CH_{3}COOH=0.2M \times 0.2(L)=0.04 \mathrm{~mole}}

Given due to adsorption, Molarity changes from 0.2 M to 0.1 M

So, moles of \mathrm{CH_3COOH} remaining in solution= 0.02 

So, 0.02 moles of are consumed by 0.06 of wood

Now, 

\mathrm{0.6 \mathrm{~g} \text { has adsorbed } 0.02 \text { mole of } \mathrm{CH}_{3} \mathrm{COOH}}

\mathrm{0.6 \mathrm{~g} \text { has adsorbed } 0.02 \times 60 \text { gram of } \mathrm{CH_{3}COOH}}

\mathrm{\text { 1 g of charcoal has adsorbed } \frac{0.02 \times 60}{0.6} \text { gram of }CH_3COOH}

\mathrm{\text { 1 g of charcoal has adsorbed } 2 \text { gram of }CH_3COOH}

So, 2 gram of acetic acid is adsorbed per gram of carbon.

Hence, the answer is 2

Posted by

shivangi.bhatnagar

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