When a long glass capillary tube of radius 0.015\; cm is dipped in a liquid, the liquid rises to a height of 15\; cm within it. If the contact angle b/w the liquid and glass to close to 0^{\circ}, the surface tension of the liquid  of the liquid, in mili newton  m^{-1} is ( \ For \ liquid \ \ \rho =900\; kg/m^{3} ,\; and \ use \ g=10m/s^{2}) Answer in closet integer.  
Option: 1 3
Option: 2 101
Option: 3 57
Option: 4 38

Answers (1)

As,

\mathrm{h}=\frac{2 \mathrm{s} \cos \theta}{\mathrm{r \rho g}}

\mathrm{0.15}=\frac{2 \mathrm{s} \cos 0^o}{\mathrm{0.015 \times 10^{-2} \times 900 \times 10}}

Surface tension=s = 0.10125 \ N/m = 101.25 \ \ milli- Newton/meter

So the closet integer is 101

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