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When an electron jumps from n=4 to n=2 then change in angular momentum is approximately:

Option: 1

1.1 x 10-34 Js


Option: 2

2.2 x 10-34 Js 


Option: 3

3.3 x 10-34 Js


Option: 4

4.1 x 10-34 Js


Answers (1)

best_answer

Bohr’s Model for Hydrogen Atom/Hydrogen like atoms -

Bohr's model :

1. Force of attraction between the nucleus and an electron is equal to centripetal force.

2. mv r= nh/2\pi ,  n = principal quantum number.

3. Energy can be absorbed or emitted when electron transfer orbit  E_{1}-E{_{2}}=h\nu

Bohr’s Model for Hydrogen Atom/Hydrogen-like atoms :

The frequency of radiation (ν) absorbed or emitted when electron jumps between two stationary states that differ in energy by ?E, is given by:

v= \Delta E/h= \left ( E_{2} -E_{1}\right )/h

E2 is higher energy state and E1 is lower energy state

-

As we have learnt,

The angular momentum of electron in nth orbit is given as:

mvr = \frac{nh}{2\Pi }

Now, for n = 4, angular momentum = \frac{4h}{2\Pi }
And, for n = 2, angular momentum = \frac{2h}{2\Pi }

Thus change in angular momentum = \frac{4h}{2\Pi }\, -\, \frac{2h}{2\Pi }
                                                    = \frac{h}{2\Pi }(4-2)

Thus, change in angular momentum = 2.2 *10-34 Js 

Therefore, Option(2) is correct

 

Posted by

shivangi.bhatnagar

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