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  •  When ion is treated with <img alt="\mathrm{KI}" src="https://entrance

 When \mathrm{Cu}^{2+}ion is treated with \mathrm{KI}, a white precipitate,\mathrm{X} appears in solution. The solution is titrated with sodium thiosulphate, the compound \mathrm{Y}is formed.\mathrm{X} and \mathrm{Y} respectively are   

Option: 1

\mathrm{X}=\mathrm{CuI}_{2}$\quad\quad $\mathrm{Y}=\mathrm{Na}_{2} \mathrm{~S}_{4} \mathrm{O}_{6}


Option: 2

\mathrm{X}=\mathrm{CuI}_{2} \quad \quad \mathrm{Y}= \mathrm{Na_{2}\, S_{2}O_{3}}


Option: 3

\mathrm{X}=\mathrm{Cu}_{2} \mathrm{I}_{2}$\quad \quad $\mathrm{Y}=\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}


Option: 4

\mathrm{X}=\mathrm{Cu}_{2} \mathrm{I}_{2}$\quad \quad $\mathrm{Y}=\mathrm{Na}_{2} \mathrm{~S}_{4} \mathrm{O}_{6}


Answers (1)

best_answer


‘M’ Electrolysis & liquation is method of purification where as hydraulic washing, leading, froth flotation are method of can conbration.

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sudhir.kumar

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