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When Uranium is bombarded with neutrons, it undergoes fission. The fission reaction can be written as :

_{92}\bigcup\; ^{235}+_{0}n^{1}\rightarrow _{56}Ba^{141}+_{36}Kr^{92}+3x+Q(energy)

where three particles named x are produced and energy Q is released. What is the name of the particles x ?

Option: 1

electron


Option: 2

\alpha - particle


Option: 3

neutron 


Option: 4

nutrino 


Answers (1)

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\sum \ Atomic \ mass \ number \ on \ LH.S. \ =235+1=236

\sum Atomic \ mass\ number \ on \ R.H.S\ =141+92+3x =233+3 x
 

LH.S = R.H.S \begin{aligned} \\ \\ \ \\ 233+3 x &=236 \\ x &=1 \end{aligned}

Mass \ number $=1,$ \\ no. of proton $=0$ \\ therefore \ particle \ will \ be \ Neutron.

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Ritika Harsh

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