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Which of the following compounds is likely to show both Frenkel abnd Schottky defects in its crystalline form ?
Option: 1 AgBr

Option: 2 CsCl

Option: 3 KBr

Option: 4 ZnS

Answers (3)



Frenkel Defect: This defect is shown by ionic solids. The smaller ion (usually cation) is dislocated from its normal site to an interstitial site.

It creates a vacancy defect at its Original site and an interstitial defect at its new location. Frenkel defect is also called dislocation defect. It does not change the density of the solid. Frenkel defect is shown by ionic substance in which there is a large difference in the size of ions, for example, ZnS, AgCl, AgBr and Agl due to small size of Zn2+ and Ag+ ions.

Schottky Defect: It is basically a vacancy defect in ionic solids. In order to maintain electrical neutrality, the number of missing cations and anions are equal.

Like a simple vacancy defect, the Schottky defect also decreases the density of the substance. The number of such defects in ionic solids is quite significant. For example, in NaCl, there are approximately 10Schottky pairs per cmat room temperature. In 1 cmthere are about 1022 ions. Thus, there is one Schottky defect per 1016 ions. The schottky defect is shown by ionic substances in which the cation and anion are of almost similar sizes. For example, NaCl, KCl, CsCl and AgBr. It may be noted that AgBr shows both, Frenkel as well as Schottky defects.

Only AgBr can exhibit both Schottky and Frenkel defect.

Therefore, Option(1) is correct.

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