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Which of the following is the negation of the statement ^{\prime \prime} For\: \: all \: \: M>0,\,there\,\,exists\,\,x \in S \,\,such \,\,that\, \,\,x \geq \mathrm{M}^{\prime \prime}?
Option: 1 There exists \mathrm{M}>0, such that x<M$ for all $x \in S
Option: 2 There exists \mathrm{M}>0, such that x<M$ for all $x \in S
Option: 3 There exists \mathrm{M}>0, such that x<M$ for all $x \in S
Option: 4 There exists \mathrm{M}>0, such that x<M$ for all $x \in S
Option: 5 There exists M>0, there exists x \in S$ such that $x \geq M
 
Option: 6 There exists M>0, there exists x \in S$ such that $x \geq M
 
Option: 7 There exists M>0, there exists x \in S$ such that $x \geq M
 
Option: 8 There exists M>0, there exists x \in S$ such that $x \geq M
 
Option: 9 There exists M>0, there exists x \in S$ such that $x<M
Option: 10 There exists M>0, there exists x \in S$ such that $x<M
Option: 11 There exists M>0, there exists x \in S$ such that $x<M
Option: 12 There exists M>0, there exists x \in S$ such that $x<M
Option: 13 There exists M>0$, such that $x \geq M$ for all $x \in S
Option: 14 There exists M>0$, such that $x \geq M$ for all $x \in S
Option: 15 There exists M>0$, such that $x \geq M$ for all $x \in S
Option: 16 There exists M>0$, such that $x \geq M$ for all $x \in S

Answers (1)

best_answer

In negation, one type of quantifier converts to other type

So negation of given statement is

'There exist M>0, such that M>0 for all x \in S^{\prime}.

The correct option is (1)

Posted by

Deependra Verma

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