Get Answers to all your Questions

header-bg qa

Which of the following pair is not isoelectronic species?
(At. no. \mathrm{Sm, 62; Er, 68; Yb, 70; Lu, 71; Eu, 63; Tb, 65; Tm, 69})
 

Option: 1

\mathrm{Sm}^{2+}$ and $\mathrm{Er}^{3+}
 


Option: 2

\mathrm{Yb}^{2+}$ and $\mathrm{Lu}^{3+}
 


Option: 3

\mathrm{Eu}^{2+}$ and $\mathrm{Tb}^{4+}
 


Option: 4

\mathrm{Tb}^{2+}$ and $\mathrm{Tm}^{4+}


Answers (1)

best_answer

\mathrm{Sm^{+2}= 60 \: electrons}
\mathrm{Er^{+3}= 65 \: electrons}
\mathrm{Tb^{+2}= 63 \: electrons}
\mathrm{Tm^{+4}= 63 \: electrons.}

\mathrm{Tb^{+2}\: and\: Tm^{+4}} have different electrons
So not isoelectronic

\Rightarrow Option (D) is correct.
      Option (A) is also correct }- \mathrm{Sm^{+2}\: and\: Fr^{+3}} are not isoelectronic.

Posted by

Divya Prakash Singh

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE