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  • Which of the following points lies on the tangent to the curve   at the point

Which of the following points lies on the tangent to the curve  x^4e^y + 2\sqrt{y + 1} = 3 at the point (1,0)?  
Option: 1 (2,2)     
Option: 2  (-2,6)   
Option: 3 (-2,4)     
Option: 4 (2,6)

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\\x^4 e^y + 2 \sqrt{y+1} = 3 \\ \\4x^3 e^y + x^4 e^y \frac{dy}{dx} + \frac{1}{\sqrt{y+1}} \frac{dy}{dx} = 0 \\ \frac{dy}{dx}_{at (1,0)} = -2 \\ \text{Equation of tangent } \\ (y-0) = -2 (x-1) \\ y = -2x + 2 \\ $ (-2,6) satisfy this equatin

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himanshu.meshram

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