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Which of the following statement is not true for glucose?

Option: 1

The penta acetate of glucose does not react with hydroxylamine to give oxime


Option: 2

Glucose reacts with hydroxylamine to form oxime


Option: 3

Glucose gives Schiff's test for aldehyde


Option: 4

Glucose exists in two crystalline forms \alpha and \beta


Answers (1)

best_answer

As we have learnt,

Evidence for Ring Structure of Glucose -
  1. Glucose does not react with sodium bisulphite. It confirms the absence of free -CHO group.
  2. Glucose does not give Schiff's test and DNP test. It confirms the absence of free -CHO group.
  3. Glucose pentaacetate does not react with hydroxylamine. It means the absence of free -CHO group.

Glucose does not react with Schiff's test because Schiff's reagent is used for aldehydes. Glucose exists in its cyclic form in which the aldehyde group is not free but is instead used for hemiacetal formation.

Therefore, Option(3) is correct.

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manish painkra

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