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  • Which of the following will have maximum stabilization due to crystal field?Option: 1 <img alt="\left[\mathrm{Ti}\left(\mathrm{H}_{2} \mathrm{O}\righ

Which of the following will have maximum stabilization due to crystal field?

Option: 1

\left[\mathrm{Ti}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}


Option: 2

\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}


Option: 3

\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}


Option: 4

\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}


Answers (1)

Stability \propto CFSE

\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}     Oxidation number of \mathrm{Co=+3}

                              \mathrm{CN^{-}} is strong field ligand

\left[\operatorname{Co}(\mathrm{CN})_{6}\right]^{3-} \Rightarrow \mathrm{d^{6}(low \; spin ):~t_{2g}^{6}\; e_g^{0}}

\mathrm{CFSE =\left [-(0.4 \times n_ {{t}_{2g}})+(0.6 \times n_ \text {eg}) \right ] \Delta_0}

              \\=-(0.4 \times 6)+(0.6 \times 0)~ \Delta _0\\ =-2.4~\Delta _0

\left[\operatorname{Co}(\mathrm{CN})_{6}\right]^{3-} has the maximum \text{CFSE} among given complexes.

Hence, the correct answer is Option (3).

Posted by

Kshitij

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