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Which one is the correct option for the two different thermodynamic processes ?


 
Option: 1 (a) only
Option: 2 (c) and (a)
Option: 3 (b) and (c)  
Option: 4 (c) and (d)

Answers (1)

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\\ \text{ Option (a) is wrong} ; \\ \text{since in adiabatic process}\ \mathrm{V} \neq constant.

Option (b) is wrong, since in isothermal process T  =  constant

Option  (c)  &  (d)  matches  isothermes  &adiabatic  formula  :

\mathrm{TV} \gamma-1=\text { constant \& } \frac{\mathrm{T}^{\gamma}}{\mathrm{p}^{\gamma-1}}=\mathrm{constant}

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Deependra Verma

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