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Which one of the following arrangements represents the correct order of the proton affinity of the given spices:

Option: 1

I^{-}< F^{-}< HS^{-}< NH_{2}^{-}

 

 

 


Option: 2

HS^{-}< NH_{2}^{-}< F^{-}<I^{-}


Option: 3

F< I< NH_{2}< HS


Option: 4

NH_{2}^{-}< HS^{-}< I^{-}< F^{-}


Answers (1)

best_answer

The species with the greatest proton affinity will be the strongest base, and its conjugate acid will be the weakest acid.

More the proton affinity, more difficult to give H+

The weakest acid will have the smallest value of Ka .

Since HI is a stronger acid than HF and HF is a stronger acid than H2S, a partial order of proton affinity is \mathrm{I^{-}<F^{-}<H S^{-}}
Since NH3 is a very weak acid, \mathrm{NH}_2^{-} must be a very strong base.

Therefore the correct order of proton affinity is
\mathrm{I^{-}<F^{-}<H S^{-}<\mathrm{NH}_2^{-}}

Option 1 is correct.
 

Posted by

Pankaj Sanodiya

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