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  • Which one of the lanthanoids given below is the most stable in divalent from?Option: 1 <img alt="\mathrm{\mathrm{Ce} \text { (Atomic Number 58) }}" s

Which one of the lanthanoids given below is the most stable in divalent from?

Option: 1

\mathrm{\mathrm{Ce} \text { (Atomic Number 58) }}


Option: 2

\mathrm{\text { Sm (Atomic Number 62) }}


Option: 3

\mathrm{\text { Eu (Atomic Number 63) }}


Option: 4

\mathrm{Yb} \text { (Atomic Number 70) }


Answers (1)

best_answer

Fact based.

Eu is most stable in divalent form among them.

\mathrm{E_{M^{3+}|M^{2+}}^{0} : Eu(-0.35~V), Yb(-1.05~V)}

Hence, Option (3) is correct.

Posted by

vinayak

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