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  • While estimating the nitrogen present in an organic compound by Kjeldahl's method, the ammonia evolved from 0.25 g of the compound neutralized 2.5 mL of <img alt="2\; \mathrm{M}\; \mathrm{H}_{2

While estimating the nitrogen present in an organic compound by Kjeldahl's method, the ammonia evolved from 0.25 g of the compound neutralized 2.5 mL of 2\; \mathrm{M}\; \mathrm{H}_{2} \mathrm{SO}_{4}. The percentage of nitrogen present in organic compound is__________.

Option: 1

56


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{NH_{3}} is neutralized by 2.5 ml of 2M \mathrm{H_{2}SO_{4}}

mole of \mathrm{\mathrm{NH}_3 \times n \text {-factor of } \mathrm{NH}_2=2.5 \times 2 \times 2 \text { meq }}

                            \mathrm{n_{\mathrm{NH}_3} \times 1=10 \text { meq }}

                    \mathrm{n_{\mathrm{NH}_3}=10 \mathrm{meq}=10 \times 10^{-3} \mathrm{~mole}}

\mathrm{\text { mass of nitrogen }=14 \times 10 \times 10^{-3}=0.14 \mathrm{~g}}

\mathrm{[\text { mass }={ mole \times molar \; mass }]}

\mathrm{%\; N = \frac{mass\; of\; nitrogen\; in \; compound}{mass\; of \; compound}\times 100=\frac{0.14}{0.25}\times 100=56%}

Answer = 56

Posted by

Ritika Harsh

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