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Engineering
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The major product of the following reaction is :

  • Option 1)

  • Option 2)

  • Option 3)

  • Option 4)

 
As we learned    Friedel Crafts reaction - Anisole reacts with an alkyl halide and acyl halide introducing alkyl and acyl groups in ortho and para positions. - wherein       Option 1) Option 2) Option 3) Option 4)
Engineering
140 Views   |  

The reagent(s) required for the following conversion are :

  • Option 1)

    (i) B_{2}H_{6}\; \; \; \; \; \; \; \; (ii)SnCl_{2}/HCl\; \; \; \; \; \; \; \; (iii)H_{3}O^{+}

     

     

     

  • Option 2)

    (i) LiAlH_{4}\; \; \; \; \; \; \; \; (ii)H_{3}O^{+}

  • Option 3)

    (i) B_{2}H_{6}\; \; \; \; \; \; \; \; (ii)DIBAL-H\; \; \; \; \; \; \; \; (iii)H_{3}O^{+}

  • Option 4)

    (i) NaBH_{4}\; \; \; \; \; \; \; \; (ii)Raney\: Ni/H_{2}\; \; \; \; \; \; \; \; (iii)H_{3}O^{+}

 
As we learned    Hydroboration oxidation reaction - Addition of water to an alkene is syn, anti-Markownikoff. - wherein       Option 1)       Option 2) Option 3) Option 4)
Engineering
115 Views   |  

The main reduction product of the following compound with NaBH4 in methanol is :

  • Option 1)

  • Option 2)

  • Option 3)

  • Option 4)

 
As we learned    Alkoxy mercuration demercuration - Reaction between alkene and alcohol in the presence of trifluoroacetate. - wherein     NaBH4 can reduce carbonyl group but it cannot reduce amide.    Option 1) Option 2) Option 3) Option 4)
Engineering
90 Views   |  

The major product of the following reaction is :

  • Option 1)

  • Option 2)

  • Option 3)

  • Option 4)

 
As we learned Alcohol formation by hydration of alkenes - Follow electrophilic addition mechanism (Markownikoff) - wherein     Option 1) Option 2) Option 3) Option 4)
Engineering
317 Views   |  

Phenol on treatment with CO2 in the presence of NaOH followed by acidification produces compound X as the
major product. X on treatment with (CH3CO)2O in the presence of catalytic amount of H2SO4 produces :

  • Option 1)

  • Option 2)

  • Option 3)

  • Option 4)

 
As we learned Kolbe's Schmidth reaction - Phenoxide ion undergo electrophilic substitution with CO2,  a weak electrophile. - wherein     Option 1) Option 2) Option 3) Option 4)
Engineering
88 Views   |  

The major product formed in the following reaction is :

  • Option 1)

  • Option 2)

  • Option 3)

  • Option 4)

 
As we learned @4581   Option 1) Option 2) Option 3) Option 4)
Engineering
859 Views   |  

Phenol reacts with methyl chloroformate in the presence of NaOH to form product A. A reacts with Br2 to form product B.
A and B are respectively :

  • Option 1)

  • Option 2)

  • Option 3)

  • Option 4)

 
As we learned Halogenation in solvents of low polarity - Monobromophends are formed, para position predominates due to steric hindrance at ortho position.  - wherein       Option 1) Option 2) Option 3) Option 4)
Engineering
244 Views   |  

Glucose on prolonged heating with HI gives :

  • Option 1)

    6-iodohexanal

  • Option 2)

    n-Hexane

  • Option 3)

    1-Hexene

  • Option 4)

    Hexanoic acid

 

As we learned

Reaction of glucose with HI -

Forms Hexane

- wherein

 

 


Option 1)

6-iodohexanal

Option 2)

n-Hexane

Option 3)

1-Hexene

Option 4)

Hexanoic acid

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Engineering
134 Views   |  

The major product formed in the following
reaction is :

  • Option 1)

  • Option 2)

  • Option 3)

  • Option 4)

 
As we have learnt,   Dehydration of alcohol to form aldehyde and ketone - Primary alcohol gives aldehyde and secondary alcohol gives ketone, in the presence of Cu at 575k. - wherein     Option 1) Option 2) Option 3) Option 4)
Engineering
155 Views   |  

On treatment of the following compound
with a strong acid, the most susceptible
site for bond cleavage is :

  • Option 1)

    C1−O2

  • Option 2)

    O2−C3

  • Option 3)

    C4−O5

  • Option 4)

    O5−C6

 
As we have learnt,   Cleavage of ether by acid - –  Products forms are alcohol and haloalkane. –  When HX is in excess - wherein    After cleavage of O2 - C3 both oxygen with negetive charge and C with positive charge are resonance stablised.   Option 1) C1−O2 Option 2) O2−C3 Option 3) C4−O5 Option 4) O5−C6
Engineering
215 Views   |  

The increasing order of the acidity of the
following carboxylic acids is :

  • Option 1)

    I < III < II < IV

  • Option 2)

    IV < II < III < I

  • Option 3)

    II < IV < III < I

  • Option 4)

    III < II < IV < I

 

As we have learnt,

 

Acidic strength of carboxylic acid -

–  More acidic than phenols or alcohols.

–  Acidity increase with the presence of a group with  -I effect in the alkyl group.Whereas it decreases with the presence of  +I group.

–  Acidity increases with increase in the number of halogen atoms on \alpha - position.

–  It decreases with increasing distance of halogen from  -COOH 

–  It increases with increase in the electronegativity of halogen.

-

 

-NO2 and -Cl is deactivating group  while -OH is ring activating group.

Ring deactivating group increases the acidic character whereas ring activating group decreases the acidic strength.

 


Option 1)

I < III < II < IV

Option 2)

IV < II < III < I

Option 3)

II < IV < III < I

Option 4)

III < II < IV < I

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Engineering
96 Views   |  

The major product of the following reaction is :

  • Option 1)

  • Option 2)

  • Option 3)

  • Option 4)

 

 

As we have learned @3524


Option 1)

This is correct

Option 2)

This is incorrect

Option 3)

This is incorrect

Option 4)

This is incorrect

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Engineering
141 Views   |  

The major product B formed in the following reaction sequence is :

  • Option 1)

  • Option 2)

  • Option 3)

  • Option 4)

 

As we have learned

Reaction of Grignard reagent with aldehyde -

With methanol yields primary alcohol, with all other aldehydes produces secondary alcohols

- wherein

 

  

 

 

 


Option 1)

This is incorrect

Option 2)

This is correct

Option 3)

This is incorrect

Option 4)

This is incorrect

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Engineering
226 Views   |  

Which of the following compounds will most readily be dehydrated to give alkene under acidic condition ?

  • Option 1)

    1-Pentanol

  • Option 2)

    4-Hydroxypentan-2-one

  • Option 3)

    3-Hydroxypentan-2-one

  • Option 4)

    2-Hydroxycyclopentanone

 
As we have learned Secondary alcohol -   group is attached to secondary carbon. - wherein    will mostly readily dehyrated to give conjugate alkene     Option 1) 1-Pentanol This is incorrect Option 2) 4-Hydroxypentan-2-one This is correct Option 3) 3-Hydroxypentan-2-one This is incorrect Option 4) 2-Hydroxycyclopentanone This is incorrect
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