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'a' for which x^{2}-ax+9= 0 can be written as square of a linear factor is

Option: 1

6


Option: 2

-6,6


Option: 3

\left ( 6,\infty \right )


Option: 4

\left ( -\infty,-6 \right )


Answers (1)

best_answer

Square of linear factor

\Rightarrow x^{2}-ax+9= \left ( x-\alpha \right )^{2}\\

                             = \left ( x-\alpha \right )\left ( x-\alpha \right )

So, both roots should be equal

\Rightarrow D= 0\\

\Rightarrow a^{2}-4\cdot9\cdot1=0\\

\Rightarrow a^{2}=36\\

\Rightarrow a=\pm 6

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