A and B together complete a work in 36 days, B and C together completes in 48 days, and A and C completes in 72 days. How long would each take to do the job?
288 days.
280 days.
285 days.
240 days.
A+B work in 1 day = 1/36…………..(1)
B+C work in 1 day = 1/48…………..(2)
A+C work in 1 day = 1/72…………..(3) Adding (1)+(2)+(3), we get
2 (A+B+C)’s 1 day work = 1/36+1/48+1/72 = 9/144 = 1/ 16
And hence (A+B+C)’s 1 day work = 1/ 32
Now 1 day work of A = 1/32-1/48 =1/96 therefore A completes the work in 96 days.
Now 1 day work of B = 1/32-1/72 =5/288 therefore A completes the work in 288/5 days.
Now 1 day work of C = 1/32-1/36 =1/288 therefore A completes the work in 288 days.