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ABCD is a trapezium such that A L \perp D C and B M \perp D C. If AB = 7 cm, BC = AD = 5 cm and AL = BM = 4 cm then
area of trap(ABCD) is 

Option: 1

40 cm2


Option: 2

50 cm2


Option: 3

60 cm2


Option: 4

80 cm2


Answers (1)

best_answer

\\C M^{2}=B C^{2}-B M^{2}=(5)^{2}-(4)^{2}=9 \Rightarrow C M=3 cm\\\\ \text{Similarly, } D L=3 cm \\\\\therefore C D=D L+L M+C M=(3+7+3) cm =13 cm\\\\ \operatorname{ar}(\operatorname{trap} . A B C D)=\left[\frac{1}{2} \times(7+13) \times 4\right] cm ^{2}=40 cm ^{2}

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sudhir.kumar

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