Applicants for the doctoral Programmes of Ambi Institute of Engineering (AIE) and Bambi Institute of Engineering (BIE) have to appear for a Common Entrance Test (CET). The test has three sections: Physics (P), Chemistry (C), and Maths CM). Among those appearing for CET, those at or above the 80th percentile in at least two sections, and at or above the 90th percentile overall, are selected for Advanced Entrance Test (AET) conducted by ATE. AET is used by ATE for final selection.
For the 200 candidates who are at or above the 9oth Percentile overall based on CET, the following are known about their performance in CET:
1. No one is below the 80th percentile in all 3 sections.
2. 150 are at or above the 80th percentile in exactly two sections.
3. The number of candidates at or above the 80th percentile only in P is the same as the number of candidates at or above the 80th percentile only in C The same is the number of candidates at or above the 80th percentile only in M.
4. Number of candidates below 80th percentile in V Number of candidates below 8oth percentile in C:
Number of candidates below 80th percentile in M = 4 : 2 : 1.
BIE uses a different Process for selection. If any candidate is appearing in the AET by ATE, BIE considers their AET score for final selection provided the candidate is at or above the 80th percentile in P. Any other candidate at or above the 80th percentile in P in CET, but who is not eligible for the AET, is required to appear in a separate test to be conducted by STE for being considered for final selection. Altogether, there are 400 candidates this year who are at or above the 80th percentile in P.
Question : If the number of candidates who are at or above the 90th percentile overall and also are at or above the 80th percentile in P in CET, is more than 100, how many candidates had to sit for the separate test for BIE?
299
310
321
330
200 candidates scored above the 90th percentile in CET.
The Venn diagram represents the number of candidates who scored above the 80th percentile in each of the three sections.
From the given information, we can see that there are a total of 200 candidates who took the CET. Of these, 150 candidates scored at or above the 90th percentile in at least two sections. These candidates are selected for AET.
The remaining 50 candidates who scored at or above the 90th percentile in at least two sections scored below the 90th percentile in one of the sections. These candidates will be considered for a separate test.
Of the 50 candidates, there are 3 candidates who scored at or above the 80th percentile in P and at or above the 90th percentile overall. These candidates are also selected for AET.
The remaining 47 candidates scored at or above the 80th percentile in P but below the 90th percentile overall. These candidates will be considered for the separate test.
Therefore, a total of 299 candidates will have to sit for the separate test.
Below can be inferred:
At or above 90th percentile in at least two sections = 150
At or above 90th percentile in P and at or above 80th percentile overall = 3
At or above 80th percentile in P but below the 90th percentile overall = 47
Total number of candidates who must sit for the separate test = 299