Directions for question :
In the recent past in Kolkata, abduction of primary-school children, which was unheard of before, suddenly was on the rise. The Police Commissioner of Kolkata IPS Mr Vineet Kumar Goyal, instructed all the schools in Kolkata to take steps to increase the security of their students during the school hours.
St Xavier’s School, Kolkata, already had a security system in place. However, the management, after a survey, decided to beef up the security at Gate D on Short Street, which was rather a secluded area. The management took the decision that there must be two guards guarding Gate D each day of the week from Monday to Saturday. The security agency they did business with sent five top security guards named Ambar, Biplab, Chandan, Dinesh and Ekram for the job.
However, they had some constraints while performing their duty :
a) None of the guards worked for three consecutive days in a week
b) Ambar did not work on Monday, Tuesday, and Wednesday
c) Biplab and Dinesh both had a service gun, and hence never worked on the same day
d) Biplab worked on alternate days and he worked with Ambar on Friday
e) Ekram worked for the maximum number of days in a week amongst all the five guards
f) Both Biplab and Dinesh worked for an odd number of days during the week
g) Two particular guards out of the five worked for the same number of days in a week
h) Each of the rest three guards worked for a distinct number of days
Question :
Which of the following statements could never be true ?
Chandan and Ekram can work together on Thursday
Biplab and Chandan can work together on Wednesday
Chandan and Dinesh can work together on Thursday
Ambar and Ekram can work together on Saturday
There are in total 6*2 = 12 guard shifts required.
That can be only fulfilled along with all the constraints given if Ekram does 4 shifts, Biplab does 3 shifts, Ambar and Chandan does 2 each, and Dinesh does 1 shift, as 4+3+2+2+1 = 12
Given below are all the possible situations of shift combinations.
The left hand table A represents Ekram working with one particular guard twice a week, and there are two possible cases which satisfy all the constraints
The right hand table B represents Ekram working with a different guard every time during the week, and here too there are two possible cases which satisfy all the constraints -
A |
Case 1 |
Case 2 |
Monday |
Biplab, Ekram |
Biplab, Ekram |
Tuesday |
Dinesh, Chandan |
Dinesh, Chandan |
Wednesday |
Biplab, Ekram |
Biplab, Ekram |
Thursday |
Ekram, Chandan |
Ambar, Ekram |
Friday |
Ambar, Biplab |
Ambar, Biplab |
Saturday |
Ambar, Ekram |
Ekram, Chandan |
B |
Case 1 |
Case 2 |
Monday |
Biplab, Ekram |
Biplab, Ekram |
Tuesday |
Ekram, Chandan/Dinesh |
Ekram, Chandan/Dinesh |
Wednesday |
Biplab, Chandan |
Biplab, Chandan |
Thursday |
Ambar, Ekram |
Ekram, Chandan/Dinesh |
Friday |
Ambar, Biplab |
Ambar, Biplab |
Saturday |
Ekram, Chandan/Dinesh |
Ambar, Ekram |
Either from Table A or Table B, and their individual two cases each, it can be seen that Chandan and Dinesh could never work together on a Thursday.