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Equation of the circle which is concentric with x^2+y^2-4x-4y+16=0 and having radius 6 unit is

Option: 1

x^2+y^2-4x+4y-28=0


Option: 2

x^2+y^2+4x+4y-28=0


Option: 3

x^2+y^2-4x-4y+28=0


Option: 4

x^2+y^2-4x-4y-28=0


Answers (1)

best_answer

Center of the circle x^2+y^2-4x-4y+16=0 is

(-g, -f) = (2, 2)

Equatio of circle with center at (2,2) and having radius 6 unit is

\\(x-2)^2+(y-2)^2=6^2\\\Rightarrow x^2-4x+4+y^2-4y+4=36\\\Rightarrow x^2+y^2-4x-4y-28=0

Posted by

jitender.kumar

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