Find 4 + 7 + 10 + 13 + 16 + . . . up to 20 terms
650
225
275
115
a = 4
d = 7 – 4 = 3
Sum of first 20 terms,
S20=n/2[2a+(n−1)d]=20/2[(2×4)+(20−1)3]
=10[8+(19×3)]=10[8+57]=650
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