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  • Funky Pizzana was required to supply pizzas to three different parties. The total number of pizzas it had to deliver was 800, 70% of which were to be delivered to Party 3 and the rest equall

Funky Pizzana was required to supply pizzas to three different parties. The total number of pizzas it had
to deliver was 800, 70% of which were to be delivered to Party 3 and the rest equally divided between
Party land Party 2.
Pizzas could be of Thin Crust (T) or Deep DIsh (0) variety and come in either Normal Cheese (NC) or Extra Cheese (EC) versions. Hence, there are four types of pizzas: T-NC, T-EC, D-NC and D-EC. Partial
information about proportions of T and NC pizzas ordered by the three parties is given below: 

 

    Thin Crust     (T) 

    Normal Cheese     (NC) 

Party 1 

    0.6 

  

Party 2 

    0.55 

    0.3 

Party 3 

  

    0.65 

Total 

    0.375 

    0.52 

 

Question : For Party 2, if 50% of the Normal Cheese pizzas were of Thin Crust variety, what was the difference between the numbers of T-EC and D-EC pizzas to be delivered to Party 2?

Option: 1

18


Option: 2

12


Option: 3

30


Option: 4

24


Answers (1)

best_answer

Given:

  • The total number of pizzas that Funky Pizzana had to deliver was 800.
  • 70% of the pizzas were to be delivered to Party 3, and the rest were to be divided equally between Party 1 and Party 2.
  • The proportion of thin crust pizzas (T) and normal cheese pizzas (NC) ordered by each party is given below:

Party

T

NC

1

0.6

0.4

2

0.55

0.3

3

0.65

0.35

Based on the given data, below can be deducted:

The number of normal cheese pizzas ordered by Party 2 is 0.3 x 120 = 36

It is given that 50% of these normal cheese pizzas were of Thin Crust variety, then 50% were of Deep-Dish variety.

So, the number of T-EC pizzas delivered to Party 2 is 66 - 18 = 48

And the number of D-EC pizzas delivered to Party 2 is 18 + 36 = 54

Therefore, the difference between the number of T-EC and D-EC pizzas to be delivered to Party 2 is 48 - 54 = 12

Posted by

chirag

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